If $A = \{x : x \text{ is a multiple of } 3\}$ and $B = \{x : x \text{ is a multiple of } 5\}$,then $A - B$ is equal to,(where $\bar{B}$ is the complement of set $B$.)
- A$\bar{A} \cap B$
- B$A \cap \bar{B}$
- C$\bar{A} \cap \bar{B}$
- D$\overline{A \cap B}$
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Given $n(U) = 20$,$n(A) = 12$,$n(B) = 9$,$n(A \cap B) = 4$,where $U$ is the universal set,$A$ and $B$ are subsets of $U$,then $n((A \cup B)^C) = $
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View SolutionTaking the set of natural numbers as the universal set,write down the complement of the following set:
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$A = \{ x : x \text{ is an even natural number} \}$
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