The relation R on the set of natural numbers | vedclass

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(B) Given the relation $R = \{(a, b) : a = 2b\}$ where $a, b \in \mathbb{N}$.By substituting values for $b$,we get $R = \{(2, 1), (4, 2), (6, 3), \dot

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$\{(1, 2), (2, 4), (3, 6), \dots\}$

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(B) Given the relation $R = \{(a, b) : a = 2b\}$ where $a, b \in \mathbb{N}$.By substituting values for $b$,we get $R = \{(2, 1), (4, 2), (6, 3), \dots\}$.The inverse relation ${R^{-1}}$ is obtained by interchanging the elements of the ordered pairs in $R$.Thus,${R^{-1}} = \{(b, a) : (a, b) \in R\} = \{(1, 2), (2, 4), (3, 6), \dots\}$.

The relation $R$ on the set of natural numbers is defined by $R = \{(a, b) : a = 2b\}$. Then ${R^{-1}}$ is:

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