If $R$ is a relation from set $A$ to set $B$,then

If $A = \{1, 2, 3\}$ and $B = \{1, 4, 6, 9\}$,and $R$ is a relation from $A$ to $B$ defined by "$x$ is greater than $y$",then the range of $R$ is:

Let $A = \{1, 2, 3, 4\}$,$B = \{1, 5, 9, 11, 15, 16\}$,and $f = \{(1, 5), (2, 9), (3, 1), (4, 5), (2, 11)\}$. Is $f$ a relation from $A$ to $B$? Justify your answer.

Let $A = \{1, 2, 3\}$ and $B = \{1, 3, 5\}$. If a relation $R$ from $A$ to $B$ is defined as $R = \{(1, 3), (2, 5), (3, 3)\}$,then find the inverse relation ${R^{ - 1}}$.

In the context of a power set containing a subset,the relation 'is a subset of' $(\subseteq)$ is:

If $n(A) = 2$ and the number of relations from set $A$ to set $B$ is $1024$, then $n(B)$ is