Let R = {(1, 3), (2, 2), (3, 2)} and S = {(2, | vedclass

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(C) The composition of relations $R \circ S$ is defined as the set of all pairs $(x, z)$ such that there exists $y \in A$ where $(x, y) \in S$ and $(y

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$\{(2, 3), (3, 2), (2, 2)\}$

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(C) The composition of relations $R \circ S$ is defined as the set of all pairs $(x, z)$ such that there exists $y \in A$ where $(x, y) \in S$ and $(y, z) \in R$. Given $S = \{(2, 1), (3, 2), (2, 3)\}$ and $R = \{(1, 3), (2, 2), (3, 2)\}$. We check each element $(x, y) \in S$: $1$. For $(2, 1) \in S$,we look for $(1, z) \in R$. We find $(1, 3) \in R$. Thus,$(2, 3) \in R \circ S$. $2$. For $(3, 2) \in S$,we look for $(2, z) \in R$. We find $(2, 2) \in R$. Thus,$(3, 2) \in R \circ S$. $3$. For $(2, 3) \in S$,we look for $(3, z) \in R$. We find $(3, 2) \in R$. Thus,$(2, 2) \in R \circ S$. Combining these,$R \circ S = \{(2, 3), (3, 2), (2, 2)\}$. Therefore,the correct option is $C$.

Let $R = \{(1, 3), (2, 2), (3, 2)\}$ and $S = \{(2, 1), (3, 2), (2, 3)\}$ be two relations on the set $A = \{1, 2, 3\}$. Then $R \circ S = $

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