Let R = {(1, 3), (2, 2), (3, 2)} and S = {(2, | vedclass

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(B) Given $S = \{(2, 1), (3, 2), (2, 3)\}$.First,find the inverse relation $S^{-1}$ by swapping the elements of each ordered pair in $S$:$S^{-1} = \{(

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$\{(1, 2), (2, 2), (3, 2)\}$

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(B) Given $S = \{(2, 1), (3, 2), (2, 3)\}$.First,find the inverse relation $S^{-1}$ by swapping the elements of each ordered pair in $S$:$S^{-1} = \{(1, 2), (2, 3), (3, 2)\}$.Now,we need to find the composition $R \circ S^{-1}$.The composition $R \circ S^{-1}$ consists of pairs $(x, z)$ such that there exists $y$ where $(x, y) \in S^{-1}$ and $(y, z) \in R$.$1$. For $(1, 2) \in S^{-1}$,we look for pairs in $R$ starting with $2$. We have $(2, 2) \in R$. Thus,$(1, 2) \in R \circ S^{-1}$.$2$. For $(2, 3) \in S^{-1}$,we look for pairs in $R$ starting with $3$. We have $(3, 2) \in R$. Thus,$(2, 2) \in R \circ S^{-1}$.$3$. For $(3, 2) \in S^{-1}$,we look for pairs in $R$ starting with $2$. We have $(2, 2) \in R$. Thus,$(3, 2) \in R \circ S^{-1}$.Combining these,$R \circ S^{-1} = \{(1, 2), (2, 2), (3, 2)\}$.

Let $R = \{(1, 3), (2, 2), (3, 2)\}$ and $S = \{(2, 1), (3, 2), (2, 3)\}$ be two relations on the set $A = \{1, 2, 3\}$. Find $R \circ S^{-1}$.

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