The solution to the equation $4^{(x^2 + 2)} - 9 \cdot 2^{(x^2 + 2)} + 8 = 0$ is:

  • A
    $x = \pm 1$
  • B
    $x = \pm 2$
  • C
    $x = \pm \sqrt{2}$
  • D
    $x = \pm \sqrt{3}$

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