(B) Given that $a^{1/x} = b^{1/y} = c^{1/z} = k$ (let $k \neq 1$).Then $a = k^x$,$b = k^y$,and $c = k^z$.We are given the condition $b^2 = ac$.Substit

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(B) Given that $a^{1/x} = b^{1/y} = c^{1/z} = k$ (let $k \neq 1$).Then $a = k^x$,$b = k^y$,and $c = k^z$.We are given the condition $b^2 = ac$.Substituting the values of $a, b, c$ in terms of $k$:$(k^y)^2 = (k^x)(k^z)$$k^{2y} = k^{x+z}$Since the bases are equal,we equate the exponents:$2y = x + z$Therefore,$x + z = 2y$.