$A$ thin hollow cylinder is open at both ends.
$(i)$ It slides without rotation.
(ii) It rolls without slipping.
If the speed is the same in both cases,the ratio of the kinetic energies is:

$A$ hollow cylinder and a solid cylinder, initially at rest at the top of an inclined plane, are rolling down without slipping. If the time taken by the hollow cylinder to reach the bottom of the inclined plane is $2 \ s$, the time taken by the solid cylinder to reach the bottom of the inclined plane is: (in $s$)

Three bodies, a ring, a solid disc, and a solid sphere, roll down the same inclined plane without slipping. The radii of the bodies are identical, and they start from rest. If $V_S, V_R$, and $V_D$ are the speeds of the sphere, ring, and disc, respectively, when they reach the bottom, then the correct option is:

$A$ spherical uniform body of radius $R$,mass $M$,and moment of inertia $I$ rolls down (without slipping) on an inclined plane making an angle $\theta$ with the horizontal. Then its acceleration is

$A$ solid cylinder of mass $M$ and radius $R$ rolls down an inclined plane of height $h$. The angular velocity of the cylinder when it reaches the bottom of the plane will be

$A$ body slides down a smooth inclined plane of inclination $\theta$ and reaches the bottom with velocity $V$. If the same body is a ring which rolls down the same inclined plane, then the linear velocity at the bottom of the plane is: