$A$ ray of light is incident normally on a prism of refractive index $1.5$,as shown. The prism is immersed in a liquid of refractive index $\mu$. The largest value of the angle $ACB$ such that the ray is totally internally reflected at the face $AC$ is $30^o$. Then the value of $\mu$ must be :

  • A
    $\frac{\sqrt{3}}{2}$
  • B
    $\frac{5}{3}$
  • C
    $\frac{4}{3}$
  • D
    $\frac{3\sqrt{3}}{4}$

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$A$ prism has a refracting angle '$A$'. The second refracting surface of the prism is silvered. $A$ light ray falling on the first refracting surface with an angle of incidence '$2A$' reaches the second surface and returns back through the same path due to reflection at the silvered surface. The refractive index of the material of the prism is:

Derive the expression $\delta = i + e - A$ for a prism.

If the angle of minimum deviation of a prism is $30^o$,the angle of incidence is $60^o$,and the prism angle is $30^o$,then the refractive index of the prism is:

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At the condition of minimum deviation,the angle of emergence is .......

For refraction through a small angled prism,the angle of deviation:

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