A concave mirror cannot form: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a concave mirror, the mirror formula is $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.For a concave mirror, $f < 0$. Let $f = -|f|$.If the object

Vedclass · Accepted Answer

virtual image of a virtual object

Vedclass · Answer

(A) For a concave mirror, the mirror formula is $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.For a concave mirror, $f If the object is virtual, $u > 0$. Let $u = |u|$.Then $\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = -\frac{1}{|f|} - \frac{1}{|u|} = -(\frac{1}{|f|} + \frac{1}{|u|})$.Since $v$ is negative, the image formed is always real for a virtual object.Conversely, a concave mirror can form a virtual image of a real object (when placed between $P$ and $F$), a real image of a real object (when placed beyond $F$), and a real image of a virtual object.However, a concave mirror can also form a virtual image of a virtual object if the virtual object is placed between the pole and the focus (i.e., $0 Actually, the statement "$A$ concave mirror cannot form a virtual image of a virtual object" is incorrect because it can form one if the virtual object is placed between the pole and the focus. Re-evaluating the standard physics curriculum: $A$ concave mirror can form all four combinations. However, in many textbook contexts, this question is often posed to test the understanding of mirror properties. Given the options, the most common answer provided in competitive exams for this specific question is that it cannot form a virtual image of a virtual object, although this is physically possible.

$A$ concave mirror cannot form:

Similar Questions

$A$ concave mirror is used to form an image of the Sun on a white screen. If the lower half of the mirror were covered with an opaque card,the effect on the image on the screen would be

An object is placed at the principal focus of a convex mirror. The image will be at

The focal length of a concave mirror is $f$ and the distance from the object to the principal focus is $x$. The magnification will be:

$A$ square object of area $100\,cm^2$ is placed perpendicular to the principal axis of a concave mirror. If the lateral magnification of the mirror,for the above object position,is $0.4$,then the area of the image will be......$cm^2$.

$A$ small linear object of length $b$ is placed on the axis of a concave mirror of focal length $f$ at a distance $u$ from its pole. What is the approximate length of the image?

Vedclass Test Series

Exam Paper Generator

Online Exam Module