A body A is thrown vertically upwards with su | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the initial velocity of body $A$ be $u$. Since it reaches a maximum height $h$,we have $u^2 = 2gh$,so $u = \sqrt{2gh}$.For body $A$,the veloci

Vedclass · Accepted Answer

Vedclass · Answer

(C) Let the initial velocity of body $A$ be $u$. Since it reaches a maximum height $h$,we have $u^2 = 2gh$,so $u = \sqrt{2gh}$.For body $A$,the velocity at time $t$ is $V_A = u - gt$.For body $B$,which is dropped from height $h$,the velocity at time $t$ is $V_B = -gt$ (taking downward as negative).Relative velocity $V_{AB} = V_A - V_B = (u - gt) - (-gt) = u$.This holds until body $B$ strikes the ground. The time taken for $B$ to fall height $h$ is $t_0 = \sqrt{2h/g}$.Since $u = \sqrt{2gh}$,we have $t_0 = \sqrt{2h/g} = \sqrt{2h/g} = u/g$.So for $0 \le t \le t_0$,$V_{AB} = u$ (a constant positive value).After $t > t_0$,body $B$ stops $(V_B = 0)$,so $V_{AB} = V_A = u - gt$.This is a linear equation with a negative slope $-g$.Thus,the graph shows a constant positive value until $t_0$,followed by a downward sloping line. This matches the representation in option $C$.

Similar Questions

$A$ $120\, m$ long train $A$ is moving with a speed of $20\, m/s$. $A$ train $B$ of length $130\, m$ is moving with a speed of $30\, m/s$ in the opposite direction. Calculate the time taken by the trains to cross each other. (in $, s$)

$A$ man is at a distance $d$ behind a bus. The bus starts from rest and moves away from the man with a constant acceleration $a$. At the same time,the man starts running towards the bus with a constant velocity $v$. Which of the following statements are correct?

$A$ person sitting in a moving train with his face towards the engine,throws a coin vertically upwards. The coin falls ahead of the person. The train:

$A$ stone falls from the top of a tower of height $100 \text{ m}$ and at the same time another stone is projected vertically upwards from the ground with a velocity $25 \text{ m/s}$. The two stones meet after (in $\text{ s}$)

Two cars $A$ and $B$ are travelling in the same direction with velocities $v_1$ and $v_2$ $(v_1 > v_2)$. When car $A$ is at a distance $d$ ahead of car $B$,the driver of car $A$ applies the brake,producing a uniform retardation $a$. There will be no collision when:

Vedclass Test Series

Exam Paper Generator

Online Exam Module