A cylinder is pure rolling up an incline plan | vedclass

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(C) When the cylinder rolls up the incline,it tends to slide down due to gravity,so the static friction acts up the incline to provide the necessary t

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is directed up the plane throughout the journey

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(C) When the cylinder rolls up the incline,it tends to slide down due to gravity,so the static friction acts up the incline to provide the necessary torque for rolling and to oppose the sliding tendency.At the highest point,the cylinder stops momentarily. As it starts rolling back down,the component of gravity $mg \sin 	heta$ acts down the plane,and the cylinder tends to slide down. To maintain pure rolling,static friction must act up the incline to provide the torque required for rotation.Therefore,in both the upward and downward journeys,the force of friction is directed up the plane.

$A$ cylinder is pure rolling up an incline plane. It stops momentarily and then rolls back. The force of friction

Similar Questions

$A$ solid uniform disk of mass $m$ rolls without slipping down a fixed inclined plane with an acceleration $a$. The frictional force on the disk due to the surface of the plane is:

$A$ ring takes times $t_1$ and $t_2$ to reach the bottom of an inclined plane of length $L$ by sliding and rolling,respectively. What is the ratio of $t_1$ to $t_2$?

$Assertion$ : The velocity of a body at the bottom of an inclined plane of given height is more when it slides down the plane,compared to when it rolls down the same plane.
$Reason$ : In rolling down,a body acquires both kinetic energy of translation and rotation.

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