A ball of mass m moving with velocity v colli | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The angular momentum $L$ of a particle about a point $P$ is given by $L = r 	imes p$,where $r$ is the position vector and $p$ is the linear momen

Vedclass · Accepted Answer

$2mvd \cos 	heta$

Vedclass · Answer

(B) The angular momentum $L$ of a particle about a point $P$ is given by $L = r 	imes p$,where $r$ is the position vector and $p$ is the linear momentum.For a particle moving with velocity $v$ at an angle $	heta$ with the horizontal,the perpendicular distance from point $P$ to the line of motion is $d \cos 	heta$.Initial angular momentum $L_i = m v (d \cos 	heta)$ (in the clockwise direction).Since the collision is perfectly elastic,the ball rebounds with the same speed $v$ at the same angle $	heta$ with the horizontal.Final angular momentum $L_f = -m v (d \cos 	heta)$ (in the counter-clockwise direction).The change in angular momentum $\Delta L = L_f - L_i = -m v d \cos 	heta - (m v d \cos 	heta) = -2m v d \cos 	heta$.The magnitude of the change in angular momentum is $2mvd \cos 	heta$.

$A$ ball of mass $m$ moving with velocity $v$ collides with a wall elastically as shown in the figure. After the impact,the change in angular momentum about point $P$ is:

Similar Questions

$A$ body of mass $5 \,kg$ moving with a uniform speed $3 \sqrt{2} \,m/s$ in the $X-Y$ plane along the line $y=x+4$. The angular momentum of the particle about the origin will be . . . . . . $kg \,m^2/s$.

The angular momentum of a single particle moving with constant speed along a circular path:

$A$ time-varying force $F = 2t$ is applied on a spool rolling as shown in the figure. The angular momentum of the spool at time $t$ about the bottommost point is:

$A$ particle is moving uniformly along a straight line as shown in the figure. During the motion of the particle from $A$ to $B$,the angular momentum of the particle about '$O$' is:

$A$ ring of mass $10 \ kg$ and diameter $0.4 \ m$ is rotating about its axis. If it completes $2100$ revolutions per minute,what is its angular momentum in $kg \cdot m^2/s$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module