A particle is moving uniformly along a straig | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The angular momentum $L$ of a particle about a point $O$ is given by the cross product $L = \vec{r} 	imes \vec{p} = \vec{r} 	imes (m\vec{v})$.Th

Vedclass · Accepted Answer

remains constant

Vedclass · Answer

(A) The angular momentum $L$ of a particle about a point $O$ is given by the cross product $L = \vec{r} 	imes \vec{p} = \vec{r} 	imes (m\vec{v})$.The magnitude of angular momentum is $L = mvr \sin(	heta)$,where $r$ is the position vector of the particle from the origin $O$,$v$ is the velocity,and $	heta$ is the angle between $\vec{r}$ and $\vec{v}$.This can also be written as $L = mv d$,where $d = r \sin(	heta)$ is the perpendicular distance from the origin $O$ to the line of motion of the particle.Since the particle is moving along a straight line,the perpendicular distance $d$ from the origin $O$ to the line of motion remains constant throughout the motion.Since the mass $m$ and the speed $v$ are also constant (uniform motion),the product $mvd$ remains constant.Therefore,the angular momentum of the particle about $O$ remains constant during the motion from $A$ to $B$.

$A$ particle is moving uniformly along a straight line as shown in the figure. During the motion of the particle from $A$ to $B$,the angular momentum of the particle about '$O$' is:

Similar Questions

The angular momentum of a single particle moving with constant speed along a circular path:

$A$ ball of mass $m$ moving with velocity $v$ collides with a wall elastically as shown in the figure. After the impact,the change in angular momentum about point $P$ is:

$A$ solid cylinder of mass $20 \ kg$ rotates about its axis with an angular speed of $100 \ rad \cdot s^{-1}$. The radius of the cylinder is $0.25 \ m$. The magnitude of its angular momentum about the axis of the cylinder is ........ $J \cdot s$.

The diameter of a flywheel is $1 \,m$. It has a mass of $20 \,kg$. It is rotating about its axis with a speed of $120$ rotations in one minute. Its angular momentum in $kg-m^2/s$ is (in $4$)

The angular momentum of a system of particles changes if:

Vedclass Test Series

Exam Paper Generator

Online Exam Module