XeF_4 has a total of 36 valence electrons. Se | vedclass

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(D) The total number of valence electrons in $XeF_4$ is calculated as: $8$ (from $Xe$) $+ 4 	imes 7$ (from $4F$) $= 36$ electrons. In the $XeF_4$ mol

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All of the above.

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(D) The total number of valence electrons in $XeF_4$ is calculated as: $8$ (from $Xe$) $+ 4 	imes 7$ (from $4F$) $= 36$ electrons. In the $XeF_4$ molecule,there are $4$ $Xe-F$ bonds,which consume $4 	imes 2 = 8$ electrons. Each of the $4$ fluorine atoms has $3$ lone pairs,totaling $4 	imes 3 	imes 2 = 24$ electrons. The central $Xe$ atom has $2$ lone pairs,which consume $2 	imes 2 = 4$ electrons. Summing these: $8 + 24 + 4 = 36$ electrons. Therefore,all statements are correct.

$XeF_4$ has a total of $36$ valence electrons. Select the correct statement regarding the use of valence electrons in $XeF_4$.

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