(x) C_4H_7OCl xrightarrow{NH_3} C_4H_9ON xri | vedclass

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(A) The reaction sequence involves a Hofmann bromamide degradation reaction.In this reaction,an amide is converted into a primary amine with one carbo

Vedclass · Accepted Answer

Butanoyl chloride

Vedclass · Answer

(A) The reaction sequence involves a Hofmann bromamide degradation reaction.In this reaction,an amide is converted into a primary amine with one carbon atom less than the original amide.The final product is $CH_3-CH_2-CH_2-NH_2$ (propan$-1-$amine),which has $3$ carbon atoms.Therefore,the amide intermediate $(C_4H_9ON)$ must have $4$ carbon atoms,which is butanamide $(CH_3-CH_2-CH_2-CONH_2)$.Butanamide is formed by the reaction of butanoyl chloride $(CH_3-CH_2-CH_2-COCl)$ with $NH_3$.Thus,compound $x$ is butanoyl chloride.

$(x) \ C_4H_7OCl$ $\xrightarrow{NH_3} C_4H_9ON$ $\xrightarrow[KOH]{Br_2} CH_3-CH_2-CH_2-NH_2$. Compound $x$ is

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