C_6H_6 + CH_3CH_2CH_2Cl + AlCl_3 to X (Major | vedclass

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(D) $1$. Friedel-Crafts alkylation of benzene with $n$-propyl chloride $(CH_3CH_2CH_2Cl)$ in the presence of $AlCl_3$ leads to rearrangement of the ca

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(D) $1$. Friedel-Crafts alkylation of benzene with $n$-propyl chloride $(CH_3CH_2CH_2Cl)$ in the presence of $AlCl_3$ leads to rearrangement of the carbocation. The primary propyl carbocation rearranges to the more stable secondary isopropyl carbocation. Thus,$X$ is isopropylbenzene (cumene).$2$. Nitration of cumene $(X)$ with $HNO_3 + H_2SO_4$ gives $p$-nitrocumene $(Y)$ as the major product due to steric hindrance at the ortho position.$3$. Reduction of $p$-nitrocumene $(Y)$ with $Sn + HCl$ gives $p$-isopropylaniline $(Z)$.$4$. Sulfonation of $p$-isopropylaniline $(Z)$ with $H_2SO_4 + SO_3$ (fuming sulfuric acid) occurs at the ortho position relative to the $-NH_2$ group (which is a strong activating group) to give $W$ ($2$-amino$-5-$isopropylbenzenesulfonic acid).

$C_6H_6 + CH_3CH_2CH_2Cl + AlCl_3 \to X$ (Major product)
$X$ (Major product) $\xrightarrow{HNO_3 + H_2SO_4} Y$ (Major product) $\xrightarrow{Sn + HCl} Z$ $\xrightarrow{H_2SO_4 + SO_3} W$
$W$ is

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$C_6H_6 + CH_3CH_2CH_2Cl + AlCl_3 \to X$ (Major product)$X$ (Major product) $\xrightarrow{HNO_3 + H_2SO_4} Y$ (Major product) $\xrightarrow{Sn + HCl} Z$ $\xrightarrow{H_2SO_4 + SO_3} W$$W$ is