CH_2(COOH)_2 xrightarrow{P_4O_{10}, , 150^cir | vedclass

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(B) The dehydration of malonic acid $(CH_2(COOH)_2)$ using phosphorus pentoxide $(P_4O_{10})$ at $150^\circ C$ results in the formation of carbon subo

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carbon suboxide

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(B) The dehydration of malonic acid $(CH_2(COOH)_2)$ using phosphorus pentoxide $(P_4O_{10})$ at $150^\circ C$ results in the formation of carbon suboxide $(C_3O_2)$.The chemical reaction is:$3 CH_2(COOH)_2 \xrightarrow{P_4O_{10}, \, 150^\circ C} 3 C_3O_2 + 4 H_3PO_4$Therefore,compound $(X)$ is carbon suboxide.

$CH_2(COOH)_2 \xrightarrow{P_4O_{10}, \, 150^\circ C} X$
Compound $(X)$ is

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$CH_2(COOH)_2 \xrightarrow{P_4O_{10}, \, 150^\circ C} X$Compound $(X)$ is