In the addition of HOBr to (I) Cl_3C-CH=CH_2 | vedclass

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(C) In $(II)$ $CH_3-CH=CH_2$,the $+I$ effect of the methyl group stabilizes the carbocation at $C_2$. Thus,$Br^{+}$ (electrophile) adds to $C_1$ and $

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$Br$ is at $C_1$ in $II$ and $C_2$ in $I$

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(C) In $(II)$ $CH_3-CH=CH_2$,the $+I$ effect of the methyl group stabilizes the carbocation at $C_2$. Thus,$Br^{+}$ (electrophile) adds to $C_1$ and $OH^{-}$ (nucleophile) adds to $C_2$.In $(I)$ $Cl_3C-CH=CH_2$,the strong $-I$ effect of the $CCl_3$ group destabilizes the carbocation at $C_2$. Therefore,$Br^{+}$ adds to $C_2$ to form a relatively more stable carbocation at $C_1$. Thus,$Br$ is at $C_1$ in $II$ and at $C_2$ in $I$.

In the addition of $HOBr$ to $(I)$ $Cl_3C-CH=CH_2$ and $(II)$ $CH_3-CH=CH_2$:

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