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(B) We know that the set difference $A - B$ is defined as $A \cap B^c$.Substituting this into the expression,we get:$A - (A - B) = A - (A \cap B^c)$Us

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$A \cap B$

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(B) We know that the set difference $A - B$ is defined as $A \cap B^c$.Substituting this into the expression,we get:$A - (A - B) = A - (A \cap B^c)$Using the property $X - Y = X \cap Y^c$,we have:$A - (A \cap B^c) = A \cap (A \cap B^c)^c$By De Morgan's Law,$(A \cap B^c)^c = A^c \cup (B^c)^c = A^c \cup B$.So,$A \cap (A^c \cup B) = (A \cap A^c) \cup (A \cap B)$.Since $A \cap A^c = \emptyset$,we get $\emptyset \cup (A \cap B) = A \cap B$.Therefore,$A - (A - B) = A \cap B$.

$A - (A - B)$ is

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