(B) In a parallel circuit,the voltage across each component is the same as the battery voltage.Voltage across bulb $1$ $(V_1)$ $= 6.0\,V$.Voltage acro

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(B) In a parallel circuit,the voltage across each component is the same as the battery voltage.Voltage across bulb $1$ $(V_1)$ $= 6.0\,V$.Voltage across bulb $2$ $(V_2)$ $= 6.0\,V$.The brightness of a bulb is determined by the power dissipated,given by $P = \frac{V^2}{R}$.For bulb $1$: $P_1 = \frac{6^2}{3} = \frac{36}{3} = 12\,W$.For bulb $2$: $P_2 = \frac{6^2}{6} = \frac{36}{6} = 6\,W$.Since $P_1 > P_2$,bulb $1$ will glow brighter.

Class 12 Physics Current Electricity Electrical Energy and Power

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$A$ $6.0\,V$ battery is connected to two light bulbs as shown in the figure. Light bulb $1$ has a resistance of $3\,\Omega$ while light bulb $2$ has a resistance of $6\,\Omega$. The battery has negligible internal resistance. Which bulb will glow brighter?

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A
Bulb $1$ will glow more first and then its brightness will become less than bulb $2$
B
Bulb $1$
C
Bulb $2$
D
Both glow equally

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$A$ $6.0\,V$ battery is connected to two light bulbs as shown in the figure. Light bulb $1$ has a resistance of $3\,\Omega$ while light bulb $2$ has a resistance of $6\,\Omega$. The battery has negligible internal resistance. Which bulb will glow brighter?

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