A 20 cm long capillary tube is dipped in wat | vedclass

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(C) The height of the water column in a capillary tube is given by the formula $h = \frac{2S \cos 	heta}{r ho g}$,where $S$ is the surface tension,

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$20$

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(C) The height of the water column in a capillary tube is given by the formula $h = \frac{2S \cos 	heta}{r ho g}$,where $S$ is the surface tension,$	heta$ is the angle of contact,$r$ is the radius of the tube,$ho$ is the density of the liquid,and $g$ is the acceleration due to gravity.In a freely falling elevator,the effective acceleration due to gravity is $g_{eff} = 0$.As $g_{eff} 	o 0$,the height $h$ of the water column tends to infinity $(h \propto \frac{1}{g})$.However,the water column is constrained by the length of the capillary tube.Therefore,the water will rise to fill the entire length of the tube.Thus,the length of the water column in the tube will be $20 \ cm$.

$A$ $20 \ cm$ long capillary tube is dipped in water. The water rises up to $8 \ cm$. If the entire arrangement is put in a freely falling elevator,the length of the water column in the capillary tube will be (in $cm$)?

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