A 20, m deep well with diameter 7, m is dug a | vedclass

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(C) The shape of the well is cylindrical.Depth $(h)$ of the well $= 20\, m$.Radius $(r)$ of the circular end of the well $= \frac{7}{2}\, m = 3.5\, m$

Vedclass · Accepted Answer

$2.5$

Vedclass · Answer

(C) The shape of the well is cylindrical.Depth $(h)$ of the well $= 20\, m$.Radius $(r)$ of the circular end of the well $= \frac{7}{2}\, m = 3.5\, m$.Area of the platform $= 	ext{Length} 	imes 	ext{Breadth} = 22\, m 	imes 14\, m = 308\, m^2$.Let the height of the platform be $H$.Since the volume of the soil dug from the well is equal to the volume of the soil spread on the platform:Volume of soil from well $= \pi r^2 h = \frac{22}{7} 	imes (3.5)^2 	imes 20 = \frac{22}{7} 	imes \frac{49}{4} 	imes 20 = 22 	imes 7 	imes 5 = 770\, m^3$.Volume of soil on platform $= 	ext{Area of platform} 	imes H = 308 	imes H$.Equating the volumes: $308 	imes H = 770$.$H = \frac{770}{308} = 2.5\, m$.Therefore,the height of the platform is $2.5\, m$.

$A$ $20\, m$ deep well with diameter $7\, m$ is dug and the earth from digging is evenly spread out to form a platform $22\, m$ by $14\, m$. Find the height of the platform. (in $m$) [Take $\pi=\frac{22}{7}$]

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