A 2.6 ,m long ladder leans on a wall such tha | vedclass

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Question

(A) Let the length of the ladder be the hypotenuse $h = 2.6 \,m$.Let the distance of the lower end from the wall be the base $b = 1 \,m$.Let the heigh

Vedclass · Accepted Answer

$2.4$

Vedclass · Answer

(A) Let the length of the ladder be the hypotenuse $h = 2.6 \,m$.Let the distance of the lower end from the wall be the base $b = 1 \,m$.Let the height reached by the ladder on the wall be $a$.According to the Pythagorean theorem,$a^2 + b^2 = h^2$.Substituting the values: $a^2 + (1)^2 = (2.6)^2$.$a^2 + 1 = 6.76$.$a^2 = 6.76 - 1 = 5.76$.$a = \sqrt{5.76} = 2.4 \,m$.Thus,the upper end reaches a height of $2.4 \,m$ on the wall.

$A$ $2.6 \,m$ long ladder leans on a wall such that its lower end remains $1 \,m$ away from the base of the wall. Then,its upper end reaches to the height of .....$m$ on the wall.

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