A 100 , g of iron nail is hit by a 1.5 , kg h | vedclass

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(C) The kinetic energy of the hammer is given by $K.E. = \frac{1}{2} mv^2 = \frac{1}{2} 	imes 1.5 	imes (60)^2 = 0.75 	imes 3600 = 2700 \, J$.Accor

Vedclass · Accepted Answer

$16.07$

Vedclass · Answer

(C) The kinetic energy of the hammer is given by $K.E. = \frac{1}{2} mv^2 = \frac{1}{2} 	imes 1.5 	imes (60)^2 = 0.75 	imes 3600 = 2700 \, J$.According to the problem,one-fourth of this energy is used to heat the iron nail.Heat energy absorbed by the nail $Q = \frac{1}{4} 	imes 2700 = 675 \, J$.The formula for heat absorbed is $Q = mc\Delta T$,where $m = 100 \, g$,$c = 0.42 \, Jg^{-1} {}^{\circ}C^{-1}$,and $\Delta T$ is the rise in temperature.Substituting the values: $675 = 100 	imes 0.42 	imes \Delta T$.$675 = 42 	imes \Delta T$.$\Delta T = \frac{675}{42} \approx 16.07 \, ^{\circ}C$.

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