$A$ $220 \; V, 50 \; Hz$ $AC$ source is connected to a $25 \; V, 5 \; W$ lamp and an additional resistance $R$ in series (as shown in the figure) to run the lamp at its rated power. The value of $R$ (in $\Omega$) will be:

$A$ series $LR$ circuit is connected to an ac source of frequency $\omega$ and the inductive reactance is equal to $2R$. $A$ capacitance of capacitive reactance equal to $R$ is added in series with $L$ and $R$. The ratio of the new power factor to the old one is

Study the circuits $(a)$ and $(b)$ shown in the figure and answer the following questions.
$(a)$ Under which conditions would the $rms$ currents in the two circuits be the same?
$(b)$ Can the $rms$ current in circuit $(b)$ be larger than that in $(a)$?

In an $LCR$ series $ac$ circuit,the voltage across each of the components,$L, C$ and $R$ is $50\,V$. The voltage across the $LC$ combination will be........$V$.

In the given series $LCR$ circuit,if the value of $R$ is changed,then:

When the $rms$ voltages $V_L, V_C$ and $V_R$ are measured respectively across the inductor $L$,the capacitor $C$ and the resistor $R$ in a series $LCR$ circuit connected to an $AC$ source,it is found that the ratio $V_L : V_C : V_R = 1 : 2 : 3$. If the $rms$ voltage of the $AC$ source is $100 \, V$,the $V_R$ is close to........$V$