A S.H.M. is represented by x = 5sqrt{2} (sin | vedclass

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(A) Given equation: $x = 5\sqrt{2} (\sin 2\pi t + \cos 2\pi t)$.We can rewrite this as: $x = 5\sqrt{2} \sin 2\pi t + 5\sqrt{2} \cos 2\pi t$.Using the

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$10$

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(A) Given equation: $x = 5\sqrt{2} (\sin 2\pi t + \cos 2\pi t)$.We can rewrite this as: $x = 5\sqrt{2} \sin 2\pi t + 5\sqrt{2} \cos 2\pi t$.Using the identity $A \sin \omega t + B \cos \omega t = R \sin(\omega t + \phi)$,where $R = \sqrt{A^2 + B^2}$.Here,$A = 5\sqrt{2}$ and $B = 5\sqrt{2}$.Resultant amplitude $R = \sqrt{(5\sqrt{2})^2 + (5\sqrt{2})^2}$.$R = \sqrt{(25 	imes 2) + (25 	imes 2)} = \sqrt{50 + 50} = \sqrt{100} = 10 \, cm$.

$A$ $S.H.M.$ is represented by $x = 5\sqrt{2} (\sin 2\pi t + \cos 2\pi t).$ The amplitude of the $S.H.M.$ is .... $cm$.

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