$A$ $6\,\mu F$ capacitor is charged from $10\,V$ to $20\,V$. The increase in energy will be:

$A$ capacitor has two circular plates,each of radius $8\,cm$,separated by a distance of $1\,mm$. $A$ dielectric slab (dielectric constant $K = 6$) is inserted between the plates. Calculate the energy stored in the capacitor when it is connected to a $150\,V$ potential difference.

$A$ parallel plate capacitor has plate area $A$ and separation between plates is $d$. It is charged to a potential difference of $V_0$ volt. The charging battery is then disconnected and plates are pulled apart to three times the initial distance. The work done to increase the distance between the plates is $(\varepsilon_0 = \text{permittivity of free space})$

$A$ capacitor is used to store $24 \, \text{watt-hour}$ of energy at $1200 \, \text{V}$. What should be the capacitance of the capacitor?

Work done by an external agent in separating the plates of a parallel plate capacitor (disconnected from the battery) is:

Energy per unit volume for a capacitor having area $A$ and separation $d$ kept at potential difference $V$ is given by