$A$ $120 \, V$ $AC$ source is connected across a pure inductor of inductance $0.70 \, H$. If the frequency of the source is $60 \, Hz$,the current passing through the inductor is: (in $, A$)
- A$4.55$
- B$0.355$
- C$0.455$
- D$3.55$
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