For a purely inductive or a purely capacitive circuit,the power factor is

The reactance of a $25\,\mu F$ capacitor at the ac frequency of $4000\, Hz$ is

An $a.c.$ source of voltage $V$ and frequency $50\,Hz$ is connected to an inductor of $2\,H$ and negligible resistance. $A$ current of $r.m.s.$ value $I$ flows in the coil. When the frequency of the voltage is changed to $400\,Hz$ keeping the magnitude of $V$ the same,the current is now

$A$ $44 \; mH$ inductor is connected to a $220 \; V, 50 \; Hz$ $AC$ supply,and a $60 \; \mu F$ capacitor is connected to a $110 \; V, 60 \; Hz$ $AC$ supply. What is the net power absorbed by each circuit over a complete cycle? Explain your answer.

$A$ coil has an inductance of $3 \ H$. The ratio of its reactance when it is first connected to an a.c. source and then to a d.c. source is:

$A$ pure inductor of $25.0 \; mH$ is connected to a source of $220 \; V$. Find the inductive reactance and rms current in the circuit if the frequency of the source is $50 \; Hz$.