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(C) When a $P$-type semiconductor is joined with an $N$-type semiconductor,a $PN$ junction is formed.At the interface,electrons from the $N$-region di

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$10^{-6}\,m$

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(C) When a $P$-type semiconductor is joined with an $N$-type semiconductor,a $PN$ junction is formed.At the interface,electrons from the $N$-region diffuse into the $P$-region,and holes from the $P$-region diffuse into the $N$-region.This process creates a region depleted of mobile charge carriers,known as the depletion region or depletion layer.The thickness of this depletion region is typically very small,on the order of $10^{-6}\,m$ (or $1\,\mu m$).Therefore,the correct option is $C$.

$A$ $PN-$ junction has a thickness of the order of

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