$A$ bag contains $4$ white,$5$ red and $6$ green balls. Three balls are picked up randomly. The probability that a white,a red and a green ball is drawn is

  • A
    $\frac{15}{91}$
  • B
    $\frac{30}{91}$
  • C
    $\frac{20}{91}$
  • D
    $\frac{24}{91}$

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