A balanced die is thrown. Find the probabilit | vedclass

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(C) When a balanced die is thrown,the sample space $S$ is given by $S = \{1, 2, 3, 4, 5, 6\}$.The total number of possible outcomes is $n(S) = 6$.Let

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$1/3$

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(C) When a balanced die is thrown,the sample space $S$ is given by $S = \{1, 2, 3, 4, 5, 6\}$.The total number of possible outcomes is $n(S) = 6$.Let $E$ be the event that the number on the die is a multiple of $3$.The multiples of $3$ in the sample space are $3$ and $6$.Thus,the favorable outcomes are $E = \{3, 6\}$.The number of favorable outcomes is $n(E) = 2$.The probability $P(E)$ is given by the formula $P(E) = \frac{n(E)}{n(S)}$.Substituting the values,$P(E) = \frac{2}{6} = \frac{1}{3}$.

$A$ balanced die is thrown. Find the probability that the number on the die is a multiple of $3$.

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