A ball is dropped from an elevator moving upw | vedclass

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(D) Let the upward direction be positive $(+)$ and the downward direction be negative $(-)$.$1$. Acceleration of the ball with respect to the ground $

Vedclass · Accepted Answer

Both $(b)$ and $(c)$

Vedclass · Answer

(D) Let the upward direction be positive $(+)$ and the downward direction be negative $(-)$.$1$. Acceleration of the ball with respect to the ground $(a_{bG})$:Once the ball is dropped,it is in free fall under gravity. Its acceleration with respect to the ground is simply the acceleration due to gravity acting downwards.$a_{bG} = -g$$2$. Acceleration of the ball with respect to the boy $(a_{bb})$:The boy is inside the elevator,which is moving upward with acceleration '$a$'.The acceleration of the ball with respect to the boy is given by the relative acceleration formula:$a_{bb} = a_{ball} - a_{boy}$Since $a_{ball} = -g$ (downward) and $a_{boy} = +a$ (upward),$a_{bb} = -g - a = -(g + a)$Thus,the acceleration of the ball with respect to the boy is $-(g+a)$ and with respect to the ground is $-g$. Therefore,both options $(b)$ and $(c)$ are correct.

$A$ ball is dropped from an elevator moving upward with acceleration '$a$' by a boy standing in it. What is the acceleration of the ball with respect to the boy and the ground respectively? [Take upward direction as positive]

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