$A$ ball rolls from the top of a stairway with a horizontal velocity $u \; m/s$. If the steps are $h \; m$ high and $b \; m$ wide,the ball will hit the edge of the $n^{th}$ step,if $n=$

  • A
    $\frac{h u^2}{g b^2}$
  • B
    $\frac{u^2}{g b^2}$
  • C
    $\frac{2 h u^2}{g b^2}$
  • D
    $\frac{2 u^2 g}{h b^2}$

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$A$ body when projected at an angle $\theta$ with the horizontal reaches a maximum height $H$. The time of flight of the body will be ($g=$ acceleration due to gravity).

$A$ fighter jet is flying horizontally at a certain altitude with a speed of $200 \; m/s$. When it passes directly overhead an anti-aircraft gun,a bullet is fired from the gun at an angle $\theta$ with the horizontal to hit the jet. If the bullet speed is $400 \; m/s$,the value of $\theta$ will be $\dots \; ^\circ$.

Path of projectile is given by the equation $Y = P x - Q x^2$, match the following accordingly (acceleration due to gravity = $g$)
$(A)$ Range$(i)$ $\frac{P}{Q}$
$(B)$ Maximum height$(ii)$ $P$
$(C)$ Time of flight$(iii)$ $\frac{P^2}{4 Q}$
$(D)$ Tangent of projection$(iv)$ $\left(\sqrt{\frac{2}{g Q}}\right) P$

$A$ particle is projected with an angle of projection $\theta$ to the horizontal. The trajectory passes through the points $(P, Q)$ and $(Q, P)$ referred to horizontal and vertical axes ($x$-axis and $y$-axis respectively). The angle of projection $\theta$ is given by:

What is the range of a projectile? Also,provide the velocity of the projectile at its maximum height.

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