A batsman scores 87 runs in the 21^{st} match | vedclass

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Question

(A) Let the average score up to $20$ matches be $x$.The total runs scored in $20$ matches is $20x$.In the $21^{st}$ match,he scores $87$ runs,so the n

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(A) Let the average score up to $20$ matches be $x$.The total runs scored in $20$ matches is $20x$.In the $21^{st}$ match,he scores $87$ runs,so the new total runs after $21$ matches is $20x + 87$.The new average after $21$ matches is $x + 2$.According to the problem,the equation is:$\frac{20x + 87}{21} = x + 2$Multiplying both sides by $21$:$20x + 87 = 21(x + 2)$$20x + 87 = 21x + 42$Rearranging the terms to solve for $x$:$87 - 42 = 21x - 20x$$x = 45$Therefore,his average before the $21^{st}$ match was $45$.

$A$ batsman scores $87$ runs in the $21^{st}$ match of his career. His average runs per match increase by $2.$ What is his average before the $21^{st}$ match?

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