A block of ice with mass m falls into a lake. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the block of ice fall from a height $h$.When the block of ice falls into the lake,its gravitational potential energy is converted into heat en

Vedclass · Accepted Answer

$\frac{L}{5g}$

Vedclass · Answer

(A) Let the block of ice fall from a height $h$.When the block of ice falls into the lake,its gravitational potential energy is converted into heat energy upon impact.This heat energy is responsible for melting a portion of the ice.The potential energy lost by the block is $PE = mgh$.The heat required to melt a mass $m/5$ of ice is $Q = (m/5)L$.Equating the potential energy to the heat energy,we get:$mgh = \frac{m}{5}L$Canceling $m$ from both sides,we have:$gh = \frac{L}{5}$Solving for $h$,we get:$h = \frac{L}{5g}$

$A$ block of ice with mass $m$ falls into a lake. After impact,a mass of ice $m/5$ melts. Both the block of ice and the lake have a temperature of $0^{\circ}C$. If $L$ represents the latent heat of fusion,the minimum distance the ice fell before striking the surface is

Similar Questions

Compared to a burn due to water at $100^{\circ}C$,a burn due to steam at $100^{\circ}C$ is

Explain the three states of matter and the process of change in states.

The figure given below shows the cooling curve of a pure wax material after heating. It cools from $A$ to $B$ and solidifies along $BD$. If $L$ and $C$ are the respective values of latent heat and the specific heat of the liquid wax,the ratio $L/C$ is

Liquid oxygen at $50\ K$ is heated to $300\ K$ at a constant pressure of $1\ atm$. The rate of heating is constant. Which of the following graphs represents the variation of temperature with time?

The graph signifies:

Vedclass Test Series

Exam Paper Generator

Online Exam Module