$A$ blue colouration is not obtained when:
- AAmmonium hydroxide dissolves in copper sulphate
- BCopper sulphate solution reacts with $K_4[Fe(CN)_6]$
- CFerric chloride reacts with sodium ferrocyanide
- DAnhydrous $CuSO_4$ is dissolved in water
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Similar Questions
The number of ions present in $2.0 \ L$ of a solution of $0.8 \ M \ K_4[Fe(CN)_6]$ is
Difficult
View SolutionThe magnetic moment (spin only) of an octahedral complex having $CFSE = -0.8 \Delta_0$ and surrounded by weak field ligands can be:
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View SolutionThe reaction of aqueous $[Ni(H_2O)_6]^{2+}$ is performed by the addition of a bidentate ligand ethane-$1,2$-diamine $(en)$. Match the following:
$[Ni(H_2O)_6]^{2+} : en$ molar ratio Colour of the product $A. 1:1$ $I. \text{Pale blue}$ $B. 1:2$ $II. \text{Blue/Purple}$ $C. 1:3$ $III. \text{Violet}$
The correct match is:
| $[Ni(H_2O)_6]^{2+} : en$ molar ratio | Colour of the product |
|---|---|
| $A. 1:1$ | $I. \text{Pale blue}$ |
| $B. 1:2$ | $II. \text{Blue/Purple}$ |
| $C. 1:3$ | $III. \text{Violet}$ |
The correct match is:
DifficultTS EAMCET 2021
View SolutionList-$I$ contains metal species and List-$II$ contains their properties.
List-$I$ List-$II$ $I$. $[Cr(CN)_6]^{4-}$ $P$. $t_{2g}$ orbitals contain $4$ electrons $II$. $[RuCl_6]^{2-}$ $Q$. $\mu$ (spin-only) $= 4.9 \ BM$ $III$. $[Cr(H_2O)_6]^{2+}$ $R$. low spin complex ion $IV$. $[Fe(H_2O)_6]^{2+}$ $S$. metal ion in $4+$ oxidation state $T$. $d^4$ species
[Given: Atomic number of $Cr = 24, Ru = 44, Fe = 26$] Match each metal species in List-$I$ with their properties in List-$II$,and choose the correct option.
| List-$I$ | List-$II$ |
| $I$. $[Cr(CN)_6]^{4-}$ | $P$. $t_{2g}$ orbitals contain $4$ electrons |
| $II$. $[RuCl_6]^{2-}$ | $Q$. $\mu$ (spin-only) $= 4.9 \ BM$ |
| $III$. $[Cr(H_2O)_6]^{2+}$ | $R$. low spin complex ion |
| $IV$. $[Fe(H_2O)_6]^{2+}$ | $S$. metal ion in $4+$ oxidation state |
| $T$. $d^4$ species |
[Given: Atomic number of $Cr = 24, Ru = 44, Fe = 26$] Match each metal species in List-$I$ with their properties in List-$II$,and choose the correct option.
The number of ions present in $2 \ L$ of a solution of $1.6 \ M \ K_4[Fe(CN)_6]$ is:
Medium
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