A boat is sent across a river with a velocity | vedclass

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(C) Let $\vec{v}_b$ be the velocity of the boat relative to the water,and $\vec{v}_r$ be the velocity of the river relative to the ground.The resultan

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(C) Let $\vec{v}_b$ be the velocity of the boat relative to the water,and $\vec{v}_r$ be the velocity of the river relative to the ground.The resultant velocity of the boat relative to the ground is $\vec{v} = \vec{v}_b + \vec{v}_r$.From the given diagram,the velocity of the boat relative to the water is represented by $\vec{AB} = 8 \, km/hr$ (directed perpendicular to the river flow).The resultant velocity of the boat relative to the ground is represented by $\vec{AC} = 10 \, km/hr$.The velocity of the river is represented by $\vec{BC}$.Since $	riangle ABC$ is a right-angled triangle with $\angle ABC = 90^\circ$,we have:$AC^2 = AB^2 + BC^2$$BC = \sqrt{AC^2 - AB^2}$$BC = \sqrt{10^2 - 8^2} = \sqrt{100 - 64} = \sqrt{36} = 6 \, km/hr$.

$A$ boat is sent across a river with a velocity of $8 \, km/hr$. If the resultant velocity of the boat is $10 \, km/hr$,then the velocity of the river is ........ $km/hr$.

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