(D) The distances covered by the body in the first,second,third,fourth,... seconds form an Arithmetic Progression $(A.P.)$: $16, 48, 80, 112, \dots$He

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(D) The distances covered by the body in the first,second,third,fourth,... seconds form an Arithmetic Progression $(A.P.)$: $16, 48, 80, 112, \dots$Here,the first term $a = 16$ and the common difference $d = 48 - 16 = 32$.The distance covered in the $n^{th}$ second is given by the $n^{th}$ term of the $A.P.$: $T_n = a + (n - 1)d$.For the $11^{th}$ second,$n = 11$.$T_{11} = 16 + (11 - 1) \times 32$$T_{11} = 16 + 10 \times 32$$T_{11} = 16 + 320 = 336\, m$.

Competitive Quantitative Aptitude Progression and Sequence Progression and Sequence

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$A$ body falls $16\, m$ in the first second of its motion,$48\, m$ in the second,$80\, m$ in the third,$112\, m$ in the fourth and so on. How far does it fall during the $11^{th}$ second of its motion? (in $m$)

A
$338$
B
$340$
C
$334$
D
$336$

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Given that $n$ $A$.$M$.'s are inserted between two sets of numbers $a, 2b$ and $2a, b$,where $a, b \in R$. Suppose further that the $m^{th}$ mean between these sets of numbers is the same,then the ratio $a:b$ equals

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$A$ body falls $16\, m$ in the first second of its motion,$48\, m$ in the second,$80\, m$ in the third,$112\, m$ in the fourth and so on. How far does it fall during the $11^{th}$ second of its motion? (in $m$)

Similar Questions

Given that $n$ $A$.$M$.'s are inserted between two sets of numbers $a, 2b$ and $2a, b$,where $a, b \in R$. Suppose further that the $m^{th}$ mean between these sets of numbers is the same,then the ratio $a:b$ equals

Let $\alpha$ and $\beta$ be the roots of $x^{2}-3x+p=0$ and $\gamma$ and $\delta$ be the roots of $x^{2}-6x+q=0$. If $\alpha, \beta, \gamma, \delta$ form a geometric progression,then the ratio $(2q+p):(2q-p)$ is:

The sum $\frac{3 \times 1}{1^2} + \frac{5 \times (1^3 + 2^3)}{1^2 + 2^2} + \frac{7 \times (1^3 + 2^3 + 3^3)}{1^2 + 2^2 + 3^2} + \dots$ up to the $10^{th}$ term is:

The sum of three numbers in a $GP$ is $105$ and their product is $8000$. Find the numbers.

If $a_1, a_2, a_3, .... a_{21}$ are in $A.P.$ and $a_3 + a_5 + a_{11} + a_{17} + a_{19} = 10$,then the value of $\sum_{r=1}^{21} a_r$ is:

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