$A$ body floats in a liquid contained in a beaker. If the whole system as shown in the figure falls freely under gravity, then the upthrust on the body due to the liquid is

$A$ streamlined body falls through air from a height $h$ on the surface of a liquid. If $d$ and $D$ $(D > d)$ represent the densities of the material of the body and the liquid respectively,then the time after which the body will be instantaneously at rest is:

$A$ cubical block of density $\rho_{b} = 600 \ kg/m^3$ floats in a liquid of density $\rho_{l} = 900 \ kg/m^3$. If the height of the block is $H = 8.0 \ cm$, then the height of the submerged part is . . . . . . $cm$. (in $.3$)

Consider a solid sphere of radius $R$ and mass density $\rho(r) = \rho_{0} \left(1 - \frac{r^{2}}{R^{2}}\right)$ for $0 < r \leq R$. The minimum density of a liquid in which it will float is

$A$ piece of steel has a weight $W$ in air,$W_1$ when completely immersed in water,and $W_2$ when completely immersed in an unknown liquid. The relative density (specific gravity) of the liquid is:

$Assertion :$ The buoyant force on a submerged rigid object can be considered to be acting at the centre of mass of the object.
$Reason :$ For a rigid body,a force field distributed uniformly through its volume can be considered to be acting at the centre of mass of the body.