A body is projected from the ground obliquely | vedclass

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(A) The power delivered by a force is given by the formula $P = \vec{F} \cdot \vec{v} = Fv \cos 	heta$,where $F$ is the force,$v$ is the velocity,and

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Increases

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(A) The power delivered by a force is given by the formula $P = \vec{F} \cdot \vec{v} = Fv \cos 	heta$,where $F$ is the force,$v$ is the velocity,and $		heta$ is the angle between the force and velocity vectors.In this case,the force is gravity,which acts vertically downwards $(F = mg)$.During the downward motion of a projectile,the velocity vector $\vec{v}$ is directed downwards,making an angle $		heta$ with the vertical force vector $\vec{F}$.As the body moves downwards,its speed $v$ increases due to the acceleration of gravity.Since the force of gravity is constant and the angle $		heta$ between the downward force and the downward velocity is $0^{\circ}$ (or decreasing towards $0^{\circ}$),the product $Fv \cos 		heta$ increases.Therefore,the power delivered by gravity increases during the downward motion.

Column-$I$	Column-$II$
$(1)$ Angle of projection for a projectile launched horizontally with constant speed	$(a)$ $0$
$(2)$ Horizontal component of acceleration for a projectile launched horizontally with constant speed	$(b)$ $0^o$

$A$ body is projected from the ground obliquely. During its downward motion,the power delivered by gravity to it:

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