A body of mass m having an initial velocity v | vedclass

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(C) For a one-dimensional elastic collision,the final velocities $v_1$ and $v_2$ of masses $m$ and $M$ are given by:$v_1 = \frac{m-M}{m+M}v + \frac{2M

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$m = M$

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(C) For a one-dimensional elastic collision,the final velocities $v_1$ and $v_2$ of masses $m$ and $M$ are given by:$v_1 = \frac{m-M}{m+M}v + \frac{2M}{m+M}u_2$$v_2 = \frac{2m}{m+M}v + \frac{M-m}{m+M}u_2$Given that the body of mass $M$ is initially stationary,$u_2 = 0$.After the collision,the body of mass $m$ comes to rest,so $v_1 = 0$.Substituting these into the equation for $v_1$:$0 = \frac{m-M}{m+M}v$Since $v 
eq 0$,we must have $m - M = 0$,which implies $m = M$.Thus,the masses must be equal for the velocity to be completely transferred to the stationary body.

$A$ body of mass $m$ having an initial velocity $v$,makes a head-on collision with a stationary body of mass $M$. After the collision,the body of mass $m$ comes to rest and only the body having mass $M$ moves. This will happen only when:

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