A body with mass 2, kg moves in one direction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) From the given potential energy graph:At $x = 2\, m$,the potential energy $U_i = 6\, J$.At $x = 5\, m$,the potential energy $U_f = 2\, J$.Since th

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) From the given potential energy graph:At $x = 2\, m$,the potential energy $U_i = 6\, J$.At $x = 5\, m$,the potential energy $U_f = 2\, J$.Since the body is released from rest at $x = 2\, m$,its initial kinetic energy $K_i = 0$.According to the law of conservation of mechanical energy,the total mechanical energy remains constant:$K_i + U_i = K_f + U_f$$0 + 6 = K_f + 2$$K_f = 6 - 2 = 4\, J$Since $K_f = \frac{1}{2} m v^2$,where $m = 2\, kg$:$4 = \frac{1}{2} 	imes 2 	imes v^2$$4 = v^2$$v = 2\, m/s$.

$A$ body with mass $2\, kg$ moves in one direction in the presence of a force which is described by the potential energy graph. If the body is released from rest at $x = 2\, m$,then its speed when it crosses $x = 5\, m$ is ................ $m/s$.

Similar Questions

Give three definitions of conservative force.

The potential energy of an object is $U(x) = (5x^2 - 4x^3) \ J$, where $x$ is the position in meters. The position at which the force becomes zero is

The potential energy of an object of mass $m$ moving in the $xy$ plane in a conservative field is given by $U = ax + by$,where $x$ and $y$ are position coordinates of the object. Find the magnitude of its acceleration.

Given the force $F = 2x^2 - 3x - 2$. Choose the correct option regarding the equilibrium positions.

State the law of conservation of energy for conservative forces and explain how it is modified for non-conservative forces.

Vedclass Test Series

Exam Paper Generator

Online Exam Module