(B) For a conservative force, the relationship between force $F$ and potential energy $U$ is given by $F = -\frac{dU}{dx}$.Given $U(x) = 5x^2 - 4x^3$.

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(B) For a conservative force, the relationship between force $F$ and potential energy $U$ is given by $F = -\frac{dU}{dx}$.Given $U(x) = 5x^2 - 4x^3$.To find the position where the force is zero, we set $F = 0$:$0 = -\frac{d}{dx}(5x^2 - 4x^3)$$0 = -(10x - 12x^2)$$12x^2 - 10x = 0$$2x(6x - 5) = 0$This gives two solutions: $x = 0 \ m$ or $x = 5/6 \ m$.Comparing this with the given options, the correct position is $5/6 \ m$.

Class 11 Physics Work, Energy and Power Conservative and Non-Conservative forces and Potential Energy

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The potential energy of an object is $U(x) = (5x^2 - 4x^3) \ J$, where $x$ is the position in meters. The position at which the force becomes zero is

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A
$1/2 \ m$
B
$5/6 \ m$
C
$1/3 \ m$
D
$2/3 \ m$

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Work, Energy and Power

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Conservative and Non-Conservative forces and Potential Energy

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The potential energy of an object is $U(x) = (5x^2 - 4x^3) \ J$, where $x$ is the position in meters. The position at which the force becomes zero is

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