$A$ bullet of mass $m$ travelling at speed $v$ strikes a block of mass $M$ at rest and gets embedded in it. Finally,both will have a combined kinetic energy of:

  • A
    $\frac{1}{2}mv^2 \times \left( \frac{m}{m + M} \right)$
  • B
    $\frac{1}{2}mv^2 \times \left( \frac{M}{m + M} \right)$
  • C
    $\frac{1}{2}mv^2 \times \left( \frac{M + m}{M} \right)$
  • D
    $\frac{1}{2}mv^2 \times \left( \frac{M + m}{m} \right)$

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