A bus decreases its speed from 80 , km , h^{- | vedclass

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(B) Initial velocity $u = 80 \, km \, h^{-1} = 80 	imes \frac{5}{18} = \frac{200}{9} \, m \, s^{-1} \approx 22.22 \, m \, s^{-1}$.Final velocity $v =

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$-2.083 \, m \, s^{-2}$

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(B) Initial velocity $u = 80 \, km \, h^{-1} = 80 	imes \frac{5}{18} = \frac{200}{9} \, m \, s^{-1} \approx 22.22 \, m \, s^{-1}$.Final velocity $v = 50 \, km \, h^{-1} = 50 	imes \frac{5}{18} = \frac{125}{9} \, m \, s^{-1} \approx 13.89 \, m \, s^{-1}$.Time $t = 4 \, s$.Using the formula for acceleration $a = \frac{v - u}{t}$:$a = \frac{\frac{125}{9} - \frac{200}{9}}{4} = \frac{-75}{9 	imes 4} = \frac{-75}{36} = -2.083 \, m \, s^{-2}$.The negative sign indicates retardation or deceleration.

$A$ bus decreases its speed from $80 \, km \, h^{-1}$ to $50 \, km \, h^{-1}$ in $4 \, s$. Find the acceleration of the bus.

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