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(D) Given that displacement $s$ is proportional to the square of time $t$,we can write $s = kt^2$,where $k$ is a constant.Velocity $v$ is the rate of

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uniform acceleration

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(D) Given that displacement $s$ is proportional to the square of time $t$,we can write $s = kt^2$,where $k$ is a constant.Velocity $v$ is the rate of change of displacement with respect to time: $v = \frac{ds}{dt} = \frac{d}{dt}(kt^2) = 2kt$.Acceleration $a$ is the rate of change of velocity with respect to time: $a = \frac{dv}{dt} = \frac{d}{dt}(2kt) = 2k$.Since $2k$ is a constant,the acceleration of the object is constant or uniform.Therefore,the object moves with uniform acceleration.

If the displacement of an object is proportional to the square of time,then the object moves with

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