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(C) Initial velocity of the train,$u = 0 \, m/s$.Final velocity of the train,$v = 40 \, km/h = 40 	imes \frac{5}{18} \, m/s = 11.11 \, m/s$.Time take

Vedclass · Accepted Answer

$0.0185$

Vedclass · Answer

(C) Initial velocity of the train,$u = 0 \, m/s$.Final velocity of the train,$v = 40 \, km/h = 40 	imes \frac{5}{18} \, m/s = 11.11 \, m/s$.Time taken,$t = 10 \, min = 10 	imes 60 \, s = 600 \, s$.Using the formula for acceleration,$a = \frac{v - u}{t}$.Substituting the values,$a = \frac{11.11 - 0}{600} = 0.0185 \, m/s^{2}$.Hence,the acceleration of the train is $0.0185 \, m/s^{2}$.

$A$ train starting from a railway station and moving with uniform acceleration attains a speed $40 \, km \, h^{-1}$ in $10$ minutes. Find its acceleration (in $m / s^{2}$).

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