A car driver leaves Bangalore at 8:30 , am an | vedclass

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Question

(D) Total distance to be covered $= 300 \, km$.Total time available $= 12:30 \, pm - 8:30 \, am = 4 \, hours$.Distance covered in $2 \, hours$ (from $

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(D) Total distance to be covered $= 300 \, km$.Total time available $= 12:30 \, pm - 8:30 \, am = 4 \, hours$.Distance covered in $2 \, hours$ (from $8:30 \, am$ to $10:30 \, am$) $= 40 \% 	ext{ of } 300 \, km = \frac{40}{100} 	imes 300 = 120 \, km$.Original speed of the car $= \frac{120 \, km}{2 \, hours} = 60 \, km/h$.Remaining distance $= 300 \, km - 120 \, km = 180 \, km$.Remaining time $= 4 \, hours - 2 \, hours = 2 \, hours$.Required speed to cover the remaining distance on time $= \frac{180 \, km}{2 \, hours} = 90 \, km/h$.Increase in speed required $= 90 \, km/h - 60 \, km/h = 30 \, km/h$.

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